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java压缩文件夹下的所有文件和选定文件及乱码解决

    博客分类:
  • java
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在linux下,如果文件夹内的文件是中文名,那么压缩后,这些文件名全部成为了乱码而无法解压,要能支持linux压缩,有两点:
1:再压缩前,要设置linux模式,
  如果是文件目录,则

ZipEntry zipEntry=new ZipEntry(basePath + System.getProperties().getProperty("file.separator"));
zipEntry.setUnixMode(755);//解决linux乱码

 

如果是文件,则

ZipEntry zipEntry=new ZipEntry(base);
 zipEntry.setUnixMode(644);//解决linux乱码

 然后在输出时强制设置编码:

 ZipOutputStream out = new ZipOutputStream(new FileOutputStream(
                zipFileName));
        out.setEncoding("GBK");//解决linux乱码

 

全部代码如下:

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.OutputStream;

import org.apache.tools.zip.ZipEntry;
import org.apache.tools.zip.ZipOutputStream;

/**
 * 文件夹压缩,支持win和linux
 * @author wlzhang
 *
 */
public class ZipUtil
{
    /**
     * @param inputFileName
     *            输入一个文件夹
     * @param zipFileName
     *            输出一个压缩文件夹,打包后文件名字
     * @throws Exception
     */
    public static OutputStream zip(String inputFileName, String zipFileName) throws Exception
    {
        return zip(zipFileName, new File(inputFileName));
    }

    private static OutputStream zip(String zipFileName, File inputFile) throws Exception
    {
        ZipOutputStream out = new ZipOutputStream(new FileOutputStream(
                zipFileName));
        out.setEncoding("GBK");//解决linux乱码
        zip(out, inputFile, "");
        out.close();
        return out;
    }

    private static void zip(ZipOutputStream out, File f, String base) throws Exception
    {
        if (f.isDirectory())
        { // 判断是否为目录
            File[] fl = f.listFiles();
            // out.putNextEntry(new org.apache.tools.zip.ZipEntry(base + "/"));
//            out.putNextEntry(new ZipEntry(base + "/"));
            ZipEntry zipEntry=new ZipEntry(base + System.getProperties().getProperty("file.separator"));
            zipEntry.setUnixMode(755);//解决linux乱码
            out.putNextEntry(zipEntry);
//            base = base.length() == 0 ? "" : base + "/";
            base = base.length() == 0 ? "" : base + System.getProperties().getProperty("file.separator");
            for (int i = 0; i < fl.length; i++)
            {
                zip(out, fl[i], base + fl[i].getName());
            }
        }
        else
        { // 压缩目录中的所有文件
            // out.putNextEntry(new org.apache.tools.zip.ZipEntry(base));
            ZipEntry zipEntry=new ZipEntry(base);
            zipEntry.setUnixMode(644);//解决linux乱码
            out.putNextEntry(zipEntry);
            FileInputStream in = new FileInputStream(f);
            int b;
            while ((b = in.read()) != -1)
            {
                out.write(b);
            }
            in.close();
        }
    }
}

 

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1 楼 josewu2009 2011-04-11  
楼主我用你的方法在window机器 上 压缩后 ,解压文件时报错

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